Sizes in MEMxxx functions are stored in ints
| Bugzilla Link | 1099 |
| Created on | Oct 15, 2013 10:29 |
| Version | svn |
| OS | All |
| Architecture | All |
Extended Description
Well, first of all this is just wrong. Secondly, size of int is not guaranteed to be as big as size of void *. Normally it is the case, but in case it won't it will be a mess. Thirdly, int is signed. Proposal (1): change all sizes to size_t, matching behaviour of malloc, realloc and free. Proposal (2): wouldn't it be nicer then to redefine malloc, realloc and free and use them without MEM prefix? Question: MEMcopy function has weird arguments: void *MEMcopy( int size, void *mem) Currently it copies SIZE bytes starting from MEM into newly allocated piece of memory... I would think that the function should be either renamed, or if not, it would be nice to match the arguments to the arguments of memcpy.
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